WebMay 17, 2013 · dob = datetime.datetime.strptime ('07-30-1950', '%m-%d-%Y') now = datetime.datetime.now () years = now.year - dob.year months = now.month - dob.month if now.day < dob.day: months -= 1 while months < 0: months += 12 years -= 1 age = ' {}y {}mo'.format (years, months) >>> print age 62y9mo Share Improve this answer Follow WebSep 8, 2005 · The idea is that the decimal age is the "real age", that considers a constant length for a year. So to account for leap years a year should be 365.25 days long, and 0.25 days is 6 hours :).

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